Aldol condensation is a reaction that results in the formation of a carbon-carbon bond when an enol (or enolate) molecule reacts with an aldehyde (or ketone). ... And an enolate ion is a compound of the anions, or negatively charged molecules, of an enol.
Sunday, November 12, 2017
Mechanism of Condensation Reaction Claisen Condensation Reaction
| Step 1: First, an acid-base reaction. The alkoxide functions as a base and removes the acidic a-hydrogen giving the reactive ester enolate. | |
| Step 2: The nucleophilic ester enolate attacks the carbonyl C of another ester in a nucleophilic substitution processgiving the tetrahedral intermediate. | |
| Step 3: The intermediate collapses, reforming the C=O, resulting in loss of the leaving group, the alkoxide, leading to the b-ketoester product. | |
The Claisen condensation is an organic reaction used to form a carbon-carbon bond between two ester molecules using an alkoxide base in alcohol to make a β-keto ester. The R group of the ester starting material, the alkoxide base, and the alcohol solvent are chosen to be the same to not end up with a mixture of products. The ester starting material must have an α-hydrogen which is abstracted by the base to form an enolate and alcohol. The enolate then attacks the carbonyl carbon of another ester molecule, an OR group is released to regenerate the base, and the final β-keto ester product is formed. The intramolecular form of the Claisen condensation is the Dieckmann condensation.
| |
Friday, November 3, 2017
Sunday, October 29, 2017
E1cB elimination reaction
The E1cB elimination reaction is a type of elimination reaction which occurs
under basic conditions, where a particularly poor leaving group (such as -OH or -OR) and an acidic hydrogen eliminate
to form an additional bond.
E1cB is a three-step process. First, a base abstracts the most acidic proton to generate a
stabilized anion. The lone pair of electrons on the anion then moves to the neighbouring
atom, thus expelling the leaving group and forming double or triple bond.
The name of the mechanism - E1cB - stands for Elimination Unimolecular conjugate Base. Elimination refers to the fact that the mechanism is an elimination reaction and will lose
two substituents. Unimolecular refers to the fact that the rate-determining step of
this reaction only involves one molecular entity. Finally, conjugate
base refers to the formation of the carbanion intermediate, which is the
conjugate base of the starting material.

An
example of the E1cB reaction mechanism in the degradation of a hemiacetal under basic conditions.
There
are two main requirements to have a reaction proceed down an E1cB mechanistic
pathway. The compound must have an acidic hydrogen
on its β-carbon and a relatively
poor leaving group on the α- carbon.
The
first step of an E1cB mechanism is the deprotonation of the β-carbon, resulting
in the formation of an anionic transition state, such as a
carbanion. The greater the stability of this transition state, the more the
mechanism will favor an E1cB mechanism. This transition state can be stabilized
through induction or delocalization of
the electron lone pair through resonance. An example of
an E1cB mechanism that has a stable transition state can be seen in the
degradation of ethiofencarb - a carbamate insecticide that has a relatively short half-life in earth's atmosphere. Upon deprotonation of
the amine, the resulting amide is
relatively stable because it is conjugated with the neighboring carbonyl. In addition to containing an acidic hydrogen on the
β-carbon, a relatively poor leaving group is also necessary. A bad leaving group is necessary because a good leaving group
will leave before the ionization of the molecule. As a
result, the compound will likely proceed through an E2 pathway. Some
examples of compounds that contain poor leaving groups and can undergo the E1cB
mechanism are alcohols and fluoroalkanes. It has also
been suggested that the E1cB mechanism is more common among alkenes eliminating to alkynes than from an alkane to alkene.[
One
possible explanation for this is that the sp2 hybridization
creates slightly more acidic protons. Although it should be noted that this
mechanism is not limited to carbon-based eliminations.
It
has been observed with other heteroatoms, such as nitrogen in the elimination of a phenol derivative from ethiofencarb.

Degradation
of ethiofencarb illustrating
the presence of a stable anion due to resonance between the amide functional
group and the carbonyl group.
Distinguishing E1cB-elimination reactions from E1- and E2-elimination reactions
|
E1
|
E2
|
E1CB
|
|
Stepwise reaction
|
Concerted reaction
|
Stepwise reaction
|
|
Carbocation Intermediate
|
removal of proton, formation of double bond, and loss of leaving
group
|
Carbanion intermediate
|
|
no kind of conclusion
|
No preference
|
kind of conclusion
|
|
Good leaving
|
groupsLeaving group
|
Poor leaving groups
|
|
Less acidic B-H
|
Acidic B-H
|
More acidic B-H
|
When trying to determine whether or not a reaction follows the
E1cB mechanism, chemical kinetics are essential. The best
way to identify the E1cB mechanism involves the use of rate laws and
the kinetic isotope effect. These techniques
can also help further differentiate between E1cB, E1, and E2-elimination
reactions.
Subscribe to:
Posts (Atom)
